Question

A rubbit gets down from a rump which its /\x=0.85m in 0.5s, The rubbit's mass is 2kg, what is the net Force?

Answer 1

Answer: 13.6 N

Step-by-step explanation:

The equation of motion for the rabbit is:

`\Delta x=V_(ox)t+(1)/(2)a_(x)t^(2)` (1)

Where:

`\Delta x=0.85 m` is the distance traveled by the rabbit

`V_(ox)=0 m/s` is the rabbit's initial velocity, assuming it started from rest

`t=0.5 s` is the time

`a_(x)` is the acceleration

Isolating
`a_(x)`:

`a_(x)=(2 \Delta x)/(t^(2))` (2)

`a_(x)=(2 (0.85 m))/((0.5)^(2))` (3)

`a_(x)=6.8 m/s^(2)` (4)

On the other hand, the force
`F_(x)` is given by:

`F_(x)=m.a_(x)` (5)

Where
`m=2 kg` is the mass of the rabbit

Substituting (4) in (5):

`F_(x)=(2 kg)(6.8 m/s^(2))` (6)

Finally:

`F_(x)=13.6 N`