Question

Sumof the square of 2 consecutive odd number is 394. Find the number

Answer 1

the answer is

11.84,13.8

Explanation

Let the first number be x,and the second be x+2

X^2+(x+2)^2=394

expand

x^2+X^2+2x+2x+4=394

2x^2+4x=390

divide the by 2

x^2+2x-195=0

using formula method

a=1

b=2

c=-195

Answer 2

The numbers are 13,15

Explanation:

Let consecutive odd numbers be (2x-1) and 2x +1

(2x - 1)² + (2x + 1)² = 394

2 * ( [2x]² + 1² ) = 394 { ( a + b)² + (a - b)² = 2(a² + b²) }

2 * (4x² + 1) = 394

4x² + 1 = 394/2

4x² + 1 = 197

4x² = 197 - 1

4x² = 196

x² = 196/4 = 49 = 7 *7

x = 7

The numbers are: 2x-1 = 2*7 - 1 = 14-1 = 13

2x + 1 = 2*7 + 1 = 14 + 1 = 15