Question

The slope-intercept form of the equation of a line that passes through point (-2, -13) is y = 54 -3. What is the point slope

form of the equation for this line?
y-13 = 564 - 2)
y- 13 = 5(x + 2)
y-2 = 5(4, - 13)
y+ 2 = 544 - 13)

Answer 1

`y+13=5(x+2)`

Explanation:

The correct question is

The slope-intercept form of the equation of a line that passes through point (-2, -13) is y = 5x -3. What is the point slope form of the equation for this line?

we have

`y=5x-3`

This is the equation of the line in slope intercept form

where

the slope is
`m=5`

the y-intercept is
`b=-3`

Remember that

The equation of the line in point-slope form is equal to

`y-y1=m(x-x1)`

we have

`m=5`

`point\ (-2,-13)`

substitute

`y-(-13)=5(x-(-2))`

`y+13=5(x+2)`