Answer:
445 g
Step-by-step explanation:
Data Given:
Volume of sucrose solution = 1.8 L
Molarity of sucrose solution = 0.718 M
mass of solute = ?
Solution:
First we will find mole of solute in a Molar Solution of sucrose
Formula used
Molarity = No. of moles of solute / of solution in L
where
solute is sucrose
Put Values in above equation
0.718 M = No. of moles of sucrose / 1.8 L
Rearrange the equation as we have to find moles of sucrose
No. of moles of sucrose = 0.718 x 1.8
No. of moles of sucrose = 1.3 mole
Now,
we have to find mass of sucrose
For this formula will use
mass in grams = no. of moles x Molar mass . . . . . .(1)
Formula of Sucrose = C₁₂H₂₂O₁₁
Molar mass of C₁₂H₂₂O₁₁ (Sucrose) = 12(12) +22(1) +11(16)
Molar mass of C₁₂H₂₂O₁₁ (Sucrose) = 144 +22 + 176
Molar mass of C₁₂H₂₂O₁₁ (Sucrose) = 342 g/mol
put values in equation 1
mass in grams = 1.3 mol x 342 g/mol
mass in grams = 444.6 g
Round the figure. So,
mass of C₁₂H₂₂O₁₁ (Sucrose) = 445 g