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Find two consecutive integers such that twice the larger is the same as two less than three times the smaller.

1 Answer

2 votes

Answer:

Ans => 4, 5

Explanation:

let the integers be x and y

if they are consecutive, that means the larger integer is one greater than the smaller

=> y = x+1

2 = 3x - 2y

3x - 2(x+1) = 2

3x - 2x - 2 = 2

x = 4

y = 4+1 = 5

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