Answer:
Policeman is correct.
Explanation:
Consider the provided information.
The tires left three skid marks of 69 ft, 70 ft, and 74 ft.
The road had a drag factor of 0.95. Your brakes were operating at 98% efficiency.
Thus, drag factor (f) = 0.95 and brakes efficiency (n) = 0.98
Compute the skid distance by finding the mean of length of 3 skids.

Therefore, the skid distance is 71 ft.
Now find the speed of car using skid speed formula:

Where, S is the speed of car, D is the skid distance, f is the drag factor and n is the beak efficiency.
Substitute the respective values in above formula.



Your speed was 44.5312 mi/h which is greater than 40 mi/hr. So policeman is correct.