Answer:
Step-by-step explanation:
Coefficient of performance of cooling apparatus
= Heat output / energy input
= T₁ / T₁ - T₂
Where T₁ = Temp of hot end and T₂ = cold end
For A
Heat output / energy input = 313 / (313 - 294)
= (Heat withdrawn + energy input )/ energy input = 313 / 19
1 + Heat withdrawn/ energy input = 313/ 19
Heat withdrawn/ energy input = 294 / 19
energy input = 19/294 x Heat withdrawn
= 19/294 x 4510
= 291.46 J
Heat deposited = 291.46 + 4510 = 4801.46 J
Similarly for B
energy input = 313-302 /302 x Heat withdrawn
= 11 / 302 X 4510
= 164.27
Heat deposited = 164.27 + 4510 = 4674.27 J