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How many real-number solutions does the equation have? 0=-5x2 +8x–7 one solution two solutions no solutions infinitely many solutions
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1 vote
How many real-number solutions does the equation have?

0=-5x2 +8x–7
one solution
two solutions
no solutions
infinitely many solutions

User Ivan Kravchenko
by
8.7k points

1 Answer

6 votes

Answer:

I'm guessing none because the discrimant (sqrt of b squared - 4ac is less than zero, signifying it has no real roots

Explanation:

have a happy holidays!

User Jemmons
by
9.3k points
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