Question

The magnetic field of an electromagnetic wave in a vacuum is Bz =(2.4μT)sin((1.05×107)x−ωt), where x is in m and t is in s. You may want to review (Pages 889 - 892) . For help with math skills, you may want to review: Rearrangement of Equations Involving Multiplication and Division Part A What is the wave's wavelength? Express your answer to three significant figures and include the appropriate units.

Answer 1

Step-by-step explanation:

Given

`B_z=(2.4\mu T)\sin (1.05* 10^7x-\omega t)`

Em wave is in the form of

`B=B_0\sin (kx-\omega t)`

where
`\omega =frequency\ of\ oscillation`

`k=wave\ constant`

`B_0=Maximum\ value\ of\ Magnetic\ Field`

Wave constant for EM wave k is

`k=1.05* 10^7 m^(-1)`

Wavelength of wave
`\lambda =(2\pi )/(k)`

`\lambda =(2\pi )/(1.05* 10^7)`

`\lambda =5.98* 10^(-7) m`