Answer:
distance is maximum at coordinates (−3, 0) , (3, 0) and minimum at distance (0,-9)
Explanation:
since the distance to the statue is
D² = (x-x₀)²+ (y-y₀)²
where x,y represents the footpath coordinates and x₀,y₀ represents the coordinates of the statue
and
y= x²-9 , for x [−3, 3]
x² = y+9
thus
D² = x²+ y²
D² = y+9 +y²
since D² is minimised when d is minimised, then
the change in distance with y is
d (D²)/dy = 2*D*d(D)/dy =2*D*( 1+2*y)
d (D²)/dy =2*D*( 1+2*y)
since D>0 , d (D²)/dy >0 for y> -1/2
therefore the distance increases with y>-1/2, then the minimum distance represents minimum y and the maximum distance represents maximum y
since
y= x²-9 for [−3, 3]
y is maximum at x=−3 and x=3 → y=0
and minimum for x=0 → y=-9
then
distance is maximum at coordinates (−3, 0) , (3, 0) and minimum at distance (0,-9)