Answer:
The change in temperature would be 129.3 °C
Step-by-step explanation:
Step 1: Data given
947000 Joule of energy is released
Mass of water = 1750 grams
Specific heat of water = 4.184 J/g°C
Step 2: Calculate change in temperature
Q = m*c*ΔT
⇒ Q = the heat released = 947000 Joules
⇒ m = the mass of water = 1750 grams
⇒ ΔT = The change of temperature = TO BE DETERMINED
947000 J = 1750 grams * 4.184 J/g°C * ΔT
ΔT = 129.3 °C
The change in temperature would be 129.3 °C