Answer:
Explanation:
Let A be the event that Flight departs on time
B be the event that Flight arrive on time
Probability that an airplane flight departs on time
![P(A)= 0.91](https://img.qammunity.org/2020/formulas/mathematics/college/pb668k7nnuuhi6sbz8y4onbrdep6zwiipn.png)
Probability that Flight arrives on time
![P(B)=0.86](https://img.qammunity.org/2020/formulas/mathematics/college/cqqkdsy8eyafumgdmw25j9hetszb0d2pf3.png)
Probability that Flight departs and arrives on time
![P\left ( A\cap B\right )=0.84](https://img.qammunity.org/2020/formulas/mathematics/college/fq8r7x5n3h6ob5w9h2ab739kqqymumwyd2.png)
Probability that a flight departed on time given that it arrives on time
![=(P\left ( A\cap B\right ))/(P\left ( B\right ))](https://img.qammunity.org/2020/formulas/mathematics/college/9u7xrly20bl768ftdd4qbla45zm6gbts1x.png)
![=(0.84)/(0.86)=0.97](https://img.qammunity.org/2020/formulas/mathematics/college/qdpckp5pptwxc8khms3ee8ng6pzzzoxtgh.png)