Question

Assume you have 28.0 grams of nitrogen and 5.0 grams of hydrogen what is the limiting reactant

Answer 1

Hydrogen is the limiting reagent.

Step-by-step explanation:

Limiting Reagent : It is the substance that get consumed when the reaction complete. It is used to determine the what amount of product will be formed.

When
`H_(2)` and
`N_(2)` react, it will produce

`NH_(3)` gas . The balance reaction can be written as:\

`N_(2)(g) + 3H_(2)(g) \rightarrow 2NH_(3)(g)`

Here, 1 mol
`N_(2)` require 3 mol
`H_(2)`

In question ,

`moles = (given\ mass)/(Molar\ mass)`

Molar mass of H2 = 2 g/mol , given mass = 5 g

`moles\ of\ H_(2) = (5)/(2)`

`H_(2)` = 2.5 mole

`moles\ of\ N_(2) = (28)/(28)`

Molar mass of N2 = 28 g/mol , given mass = 28 g

`N_(2)` = 1 mole

Since, 1 mole
`N_(2)` require 3 mole
`H_(2)`

But available , mole of
`H_(2)` = 2.5

So we need extra 0.5 moles of Hydrogen gas

Hence
`H_(2)` get consumed first , Thus Hydrogen is the limiting reagent