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2 votes
Which of the following equations illustrates the law of conservation of

matter?
A. 4A1 + 302 → 2A1203
B. 4A1 + O2 → 2A1203
C. 2A1 + 02 → A1203
D. 2A1 + 302 → Al2O3

User Gleb Esman
by
2.8k points

2 Answers

7 votes

Final answer:

The correct answer is A: 4Al + 3O2 → 2Al2O3, as it correctly represents the law of conservation of matter with 4 aluminum atoms and 6 oxygen atoms on both sides of the equation, illustrating that matter is conserved. So the correct option is A.

Step-by-step explanation:

The question asks to identify which chemical equation illustrates the law of conservation of matter. This law states that matter cannot be created or destroyed, so in a chemical reaction, the number of atoms of each element should be the same in the reactants as in the products.

Option C, 2Al + 3O2 → 2Al2O3, incorrectly shows more oxygen on the reactant side than the product side, hence does not illustrate the law of conservation of matter. Option D, 2Al + 3O2 → Al2O3, also does not balance. However, Option A, 4Al + 3O2 → 2Al2O3, correctly represents the law of conservation of matter as there are 4 aluminum (Al) atoms and 6 oxygen (O) atoms on both sides of the equation. This balanced equation maintains equal numbers of each type of atom before and after the reaction, satisfying the law of conservation of matter.

Therefore, the correct answer is A: 4Al + 3O2 → 2Al2O3.

User Jaquez
by
3.1k points
6 votes
I think the answer is letter B
User Gibatronic
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3.0k points