Question

How many grams of KCl is needed to make .75 L of a 1 M solution of KCl?

Answer 1

The answer to your question is 25.9 g of KCl

Step-by-step explanation:

Data

Grams of KCl = ?

Volume = 0.75 l

Molarity = 1 M

Formula

`Molarity = (number of moles)/(volume)`

Solve for number of moles

`Number of moles = Molarity x volume`

Substitution

Number of moles = 1 x 0.75

Simplification

Number of moles = 0.75 moles

Molecular mass KCl = 39 + 35.5 = 34.5

Use proportions to find the grams of KCl

34.5 g of KCl ---------------- 1 mol

x ---------------- 0.75 moles

x = (0.75 x 34.5) / 1

x = 25.9 g of KCl