Question

What is the solution to the following equation?
2x^2-3x+2=0 ​

Answer 1

`x = (3 +/- i √(7) )/(4)`

Explanation:

`2x^(2) -3x + 2 = 0`

a =2 b = -3 c = 2. Substitute these into the quadratic formula
`x = \frac{-b +/- \sqrt{b^(2)- 4ac} }{2a}`.

`x = \frac{-(-3)+/- \sqrt{(-3)^(2) - 4(2*2)} }{2(2)}` Simplify.

`x = \frac{3+/-\sqrt{(9)^(2) - 4(4) } }{4}` Keep simplifying...

`x = (3+/-√(9-16) )/(4)` Simplify again...

`x = (3 +/-√(-7) )/(4)` There will be an imaginary number because the number under the
`\sqrt{}` is negative, so

`x = (3+/-i√(7) )/(4)`

Answer 2

x=(3+sqrt(7)*i)/4, (3-sqrt(7)*i)/4.

Explanation:

Apply the quadratic formula.