Answer:
0.21MeV
Step-by-step explanation:
For isobar 2311Na:
Actual mass of 2311Na = 22.9898u
Number of protons = 11
Number of neutrons = 23-11 = 12
Mass of 11 protons = 11 x 1.00783u = 11.08613u
Mass of 12 neutrons = 12 x 1.00867u = 12.10404u
Theoretical ( calculated) mass of 2311Na = 11.08613 + 12.10404 = 23.19017u
Mass defect, ∆m, of 2311Na = Theoretical mass – Actual mass = 23.19017 – 22.9898 = 0.20037u
Nuclear binding energy of 2311Na = ∆m x 931.5 = 0.20037u x 931.5MeV/u = 186.64MeV.
Nuclear binding energy per nucleon = Nuclear binding energy/number of nucleons = 186.64/23 = 8.11MeV.
For isobar 2312Mg:
Actual mass of 2312Mg = 22.9941u
Number of protons = 12
Number of neutrons = 23-12 = 11
Mass of 12 protons = 12 x 1.00783u = 12.09396u
Mass of 11 neutrons = 11 x 1.00867u = 11.09537u
Theoretical ( calculated) mass of 2312Mg = 12.09396 + 11.09537 = 23.18933u
Mass defect, ∆m, of 2312Mg = Theoretical mass – Actual mass = 23.18933 – 22.9941 = 0.19523u
Nuclear binding energy of 2312Mg = ∆m x 931.5 = 0.19523u x 931.5MeV/u = 181.86MeV.
Nuclear binding energy per nucleon = Nuclear binding energy/number of nucleons = 181.86/23 = 7.90MeV.
Therefore, difference in the nuclear binding energy per nucleon between 2311Na and 2312Mg = 8.11-7.90 = 0.21MeV.