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$4000 is invested in a mutual fund that pays annual interest compounded quarterly for 15 years. What annual interest is needed to reach a value of $6000?​

1 Answer

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Answer:

The interest needed to reach that value of $6000 is 2.75%

Explanation:

Given as :

The principal that invested in mutual fund = p = $4000

The time period = t = 15 years

The Amount after 15 years = A = $6000

Let The interest needed to reach that value = r%

Now, According to question

From Compound Interest method

Amount = principal ×
(1+(\textrm rate)/(100))^(\textrm time)

Or, A = p ×
(1+(\textrm r)/(100))^(\textrm t)

Or, $6000 = $4000 ×
(1+(\textrm r)/(100))^(\textrm 15)

or,
(6000)/(4000) =
(1+(\textrm r)/(100))^(\textrm 15)

Or,
(3)/(2) =
(1+(\textrm r)/(100))^(\textrm 15)

or, 1.5 =
(1+(\textrm r)/(100))^(\textrm 15)

or,
1.5^{(1)/(15)} =
(1+(\textrm r)/(100))

or, 1.0275 =
(1+(\textrm r)/(100))

or, 1.0275 - 1 =
(r)/(100)

or, 0.0275 =
(r)/(100)

∴ r = 0.0275 × 100

I.e r = 2.75

So, The interest needed to reach that value = r = 2.75%

Hence,The interest needed to reach that value of $6000 is 2.75% Answer

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