Question

PLEASE HELP!!!Which equation goes through the point (-7, 3) and is parallel to y = −8x + 1?

y + 3 = -8(x - 7)

y + 7 = -8(x - 3)

y - 3 = -8(x + 7)

y - 3 = 8(x + 7)

Answer 1

y - 3 = -8(x + 7)

Explanation:

The equation of a line with slope m through point (h, k) is ...

y -k = m(x -h)

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The slope you want is m = -8, which is the slope of the given line.* The given point is (h, k) = (-7, 3), so the equation you're looking for is ...

y - 3 = -8(x -(-7))

The expression inside parentheses can be simplified so you have ...

y - 3 = -8(x + 7)

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* The given line is in "slope-intercept" form, which is y = mx + b. Matching this pattern to the given equation, you see that m=-8. Parallel lines have equal slope, so -8 is the slope of the line you're writing the equation for.