Question

The length of a rectangle is three times its width. If the perimeter is at most 128cm, what is the greatest possible value for the width?

Answer 1

16 cm

Explanation:

Let the width be x

The length will be 3 x since the length is three times the width

Perimeter=2(l+w) where l is length and w is width

By substituting 128 cm for perimeter, x for w and 3 x for l then

128=2(3x+x)

128=8x

`x=\frac {128}{8}=16`

Therefore, the width is 16 cm, the width is 16*3=48 cm