Question

the certain Forest covers an area of 2000 square kilometers suppose that each year this area take creases by 6% what is the equation that best represents the area of the force each year hint use the formula y equals p​

Answer 1

The equation which represent the area of forest creases each year is 2000 km²
`(0.94)^(12)` and

The area is 952 km² .

Explanation:

Given as :

The rate of depreciation of forest area each year = r = 6%

The initial area of forest = i = 2000 square kilometers

Let The final area of forest = f = x square kilometers

The time period for depreciation = 12 year

Now, According to question

The final area of forest = The initial area of forest ×
`(1-(\textrm rate)/(100))^(\textrm time)`

Or, f = i ×
`(1-(\textrm r)/(100))^(\textrm 12)`

Or, f = 2000 km² ×
`(1-(\textrm 6)/(100))^(\textrm 12)`

Or, f = 2000 km² ×
`(0.94)^(12)`

∴ f = 2000 km² × 0.475920

I.e f = 951.84 ≈ 952 km²

So, The equation which represent the area of forest creases each year = f = 952 km²

Hence,The equation which represent the area of forest creases each year is 2000 km²
`(0.94)^(12)` and the area is 952 km² . Answer