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243Am95 was present when Earth formed, but it decayed over time. The first three steps in this decay are emission of an α particle, a β− particle, and another α particle. What is the final isotope that forms after these three decay steps? Use the isotope tool on the answer palette to enter the symbol of the isotope, including both the mass number, the atomic number, and element symbol.

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Answer;an alpha particle emission is a helium nucleus represented as 4He2,when an unstable nucleus emits an alpha particle,the atomic number reduces by 2 And the mass number reduces by 4

A beta particle emission is represented by 0e-1 (electron ) or 0e+1 (positron)

243Am95 was present when Earth formed, but it decayed over time. The first three steps-example-1
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