Question

Phosphorous trichloride and phosphorous pentachloride equilibrate in the presence of molecular chlorine according to the reaction:

PCl3 (g) + Cl2 (g) → PCl5 (g)
An equilibrium mixture at 450 K contains PPCl3 = 0.124 atm, PCl2 = 0.157 atm, and PPCl5 = 1.30 atm.

What is the value of Kp at this temperature?

Answer 1

kp will be 67

Answer 2

Kp = 67

Step-by-step explanation:

The reaction is given as:

PCl3 (g) + Cl2 (g) → PCl5 (g)

Now, the Kp expression at equilibrium for this reaction is written as:

`Kp = (PPCl5) / (PPCl3)(PCl2)`

`Kp = (1.30) / (0.124)(0.157)`

`<strong>Kp = 67</strong>`

Notes:

1. Kp is the gas constant at equilibrium in terms of partial pressures of gas.
2. For a reaction: aA + bB <===> cC +dD, the expression of Kp can be written as:

`Kp = (PC)^(c).(PD)^(d) / (PA)^(a). (PB)^(b)`