Question

The specific heat of fat is roughly 1,700 J/(kgoC) whereas that for water is around 4200 J/(kgoC). A 0.63 kg solution of lipids and water is heated at a rate of 100 W for 5 minutes. During this time, the temperature of the system increases by 20oC. What is the mass of the lipid content, to the nearest hundredth of a kg, in this solution?

Answer 1

the mass of the lipid content, to the nearest hundredth of a kg, in this solution =0.46 kg

Step-by-step explanation:

Total heat content of the fat = heat content of water +heat content of the lipids

Let it be Q

the Q= (mcΔT)_lipids + (mcΔT)_water

total mass of fat M= 0.63 Kg

Q= heat supplied = 100 W in 5 minutes

ΔT= 20°C

c_lipid= 1700J/(kgoC)

c_water= 4200J/(kgoC)

then,

`100*5*60= m(1700)20+(0.63-m)(4200)20`

solving the above equation we get

m= 0.46 kg

the mass of the lipid content, to the nearest hundredth of a kg, in this solution =0.46 kg