Question

Point Q' is the image of Q(-7, -6) under the translation (x, y) + (x + 12, y + 8).

What are the coordinates of Q'?

Answer 1

The co-ordinates of Q' is (5,2).

Explanation:

Given:

Pre-image point

Q(-7,-6)

To find Image point Q' after following translation.

`(x,y)\rightarrow (x+12,y+8)`

Solution:

Translation rules:

Horizontal shift:

`(x,y)\rightarrow (x+k,y)`

when
`K>0` the point is translated
`k` units to the right.

when
`K<0` the point is translated
`k` units to the left.

Vertical shift:

`(x,y)\rightarrow (x,y+k)`

when
`K>0` the point is translated
`k` units up.

when
`K<0` the point is translated
`k` units down.

Given translation
`(x,y)\rightarrow (x+12,y+8)` shows the point is shifted 12 units to the right and 8 units up.

The point Q' can be given as:

Q'=
`(-7+12,-6+8)=(5,2)`

So, the co-ordinates of Q' is (5,2). (Answer)