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13 votes
13 votes
Please help with this I’m so confused the teacher just threw this on us and called it a day lol

Please help with this I’m so confused the teacher just threw this on us and called-example-1
User Kong Hantrakool
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2.3k points

1 Answer

15 votes
15 votes

Answer:

2A : 2.94 inches

2B : 2.718 in²

Explanation:

We are given the formula

Highest Ultimate load = max compressive strength x cross sectional area

I think there is a typo in the equations here because the above equation was repeated twice, i'm guessing the second equation should be:

Highest Ultimate load = max tensile strength x cross sectional area

Problem 2A:

Given:

Highest Ultimate load = 135,900 lb

max compressive strength (concrete) = 5,000 lbs/in²

cross sectional area = π r² ; where r is the radius of the circle in inches

simply substitute the above into the first formula and solve for r:

Highest Ultimate load = max compressive strength x cross sectional area

135,900 = 5,000 x π r²

π r² = 135900 / 5000

π r² = 27.18

r² = 27.18 / π

r = √ ( 27.18 / 3.14 )

r = 2.94 inches

Problem 2B:

Given:

Highest Ultimate load = 135,900 lb

max tensile strength (steel) = 50,000 lbs/in²

cross sectional area in inches² = (we are asked to find this)

Again simply substitute the above into the 2nd equation at the top:

Highest Ultimate load = max tensile strength x cross sectional area

135,900 = 50,000 x cross sectional area

cross sectional area = 135,900 / 50,000

cross sectional area = 2.718 in²

User Petrus Repo
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2.8k points