Question

A point source emits sound waves of amplitude A. The sound intensity at a distance d from the

source is I. What is the sound intensity at a distance 0.5d from the source when the source emits
waves of amplitude 2A?

Answer 1

The sound intensity is 16I

Step-by-step explanation:

Given:

Dsitance d = 0.5

Amplitude = 2A

To Find:

sound intensity = ?

Solution:

We Know that

`I \propto (A^(2))/(r^(2))`

When Distance is d, wuth amplitude A

The sound intensity
`I = C (A^(2))/(d^(2))`---------------------(1)

Where

C is proportionality constant

Substituting the values

`I^'= C ((2A)^(2))/(0.5^(2))`

`I^'= C (4A^(2))/(0.25d^2)`

`I^'= C (16A^(2))/(d^2)`

`I^'=  (16CA^(2))/(d^2)`

From 1 ,
`I^'=  16I`