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Arrange the listed objects according to their angular speeds, from largest to smallest.

a tire of radius 0.381 m rotating at 12.2 rpm
a bowling ball of radius 12.4 cm rotating at 0.456 rad/s
a top with a diameter of 5.09 cm spinning at 18.7∘ per second
a rock on a string being swung in a circle of radius 0.587 m with
a centripetal acceleration of 4.53 m/s2 a square, with sides 0.123 m long, rotating about its center with corners moving at a tangential speed of 0.287 m / s

1 Answer

7 votes

Answer:

Step-by-step explanation:

1 ) tire of radius 0.381 m rotating at 12.2 rpm

12.2 rpm = 12.2 /60 rps

n = .20333 rps

angular speed

= 2πn

= 2 x 3.14 x .20333

= 1.277 rad / s

2 ) a bowling ball of radius 12.4 cm rotating at 0.456 rad/s

angular speed = .456 rad/s

3 ) a top with a diameter of 5.09 cm spinning at 18.7∘ per second

18.7° per second = (18.7 / 180) x 3.14 rad/s

= .326 rad/s

4 )

a rock on a string being swung in a circle of radius 0.587 m with

a centripetal acceleration of 4.53 m/s2

centripetal acceleration = ω²R

ω is angular velocity and R is radius

4.53 = ω² x .587

ω = 2.78 rad / s

5 )a square, with sides 0.123 m long, rotating about its center with corners moving at a tangential speed of 0.287 m / s

The radius of the circle in which corner is moving

= .123 x √2

=.174 m

angular velocity = linear velocity / radius

.287 / .174

1.649 rad / s

The perfect order is

4 ) > 5> 1 >2>3.

User PierreD
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