Question

A large container contains a large amount of water. A hole is drilled on the wall of the container, at a vertical distance h = 0.54 m below the surface of the water. The water surface drops very slowly and its speed is approximately zero. Keep 2 decimal places in all answers. (a) Find the speed v (in m/s) at which water squirts out of the hole.

Answer 1

Speed can be found through the application of concepts related to potential energy and kinetic energy, for which you have

`KE = PE`

`(1)/(2)mv^2 = mgh`

Where,

m = mass

v = Velocity

g = Gravitational acceleration

h = Height

Re-arrange to find the velocity we have,

`v^2 = 2gh`

`v = √(2gh)`

`v = √(2(9.8)(0.54))`

`v = 3.253m/s`

Therefore the speed at which water squirts out of the hole is .3253m/s