Answer:
a)
![z_(critical) \text{ at 0.05 level of significance } = \pm 1.96](https://img.qammunity.org/2020/formulas/mathematics/college/fa8n6apzv73lo3q4f4nqtxathrecc7p7vu.png)
b)
![t_(critical) \text{ at 0.05 level of significance, 14 degree of freedom } = \pm 2.144](https://img.qammunity.org/2020/formulas/mathematics/high-school/nsy07zisoss9p704hixtwpo28ggkptvrxm.png)
Explanation:
We are given the following information in the question:
Sample size = 15
The population is normally distributed and the mean height of the population is going to be estimated with 95% confidence.
We have to find the appropriate critical value that should be used to build the 95 confidence level.
Confidence interval:
![\mu \pm \text{ critical value }(\sigma)/(√(n))](https://img.qammunity.org/2020/formulas/mathematics/high-school/89xgmqvyfvvq6i15zqlzuvfna2ow9153pd.png)
If the population standard deviation is given, we use the z-critical value.
![z_(critical) \text{ at 0.05 level of significance } = \pm 1.96](https://img.qammunity.org/2020/formulas/mathematics/college/fa8n6apzv73lo3q4f4nqtxathrecc7p7vu.png)
If the population standard deviation is not given, we use the t-critical value.
![t_(critical) \text{ at 0.05 level of significance, 14 degree of freedom } = \pm 2.144](https://img.qammunity.org/2020/formulas/mathematics/high-school/nsy07zisoss9p704hixtwpo28ggkptvrxm.png)