Answer:
The ultimate BOD of waste water is 265 milligram per Liter.
Step-by-step explanation:
To start with and properly determine the ultimate BOD of the waste water, we need to determine the volume of water used by the population in the city within five days.
Therefore, 50000 people × 430 Liters ÷ day-person × 5 days
1.08 × 10∧8 Liters
The mass BOD5 by the city population in 5 days is therefore,
0.1 kilogram × BOD5 ÷ day-person × 50000 people × 5 days
2.5 × 10 ∧ 4 BOD5
The 5 days BOD of waste water is therefore,
5d = 2.5 × 10 ∧ 4 / 1.08 × 10 ∧ 8 Liters × 1000grams ÷ 1 kilogram × 1000mg ÷ 1gram
233 milligram / liter
The ultimate BOD, is therefore,
ULo = 5d ÷ (1 - e ∧ -k5)
Solving this further, we derive
265 milligram per Liter.