Question

A local zoo has flamingos and elephants in one exhibit. There are 16 animals in the exhibit, and the animals have a total of 52 legs. How many of each type of animal are in the exhibit?​

Answer 1

• 6 flamingos and 10 elephants

Explanation:

Let the number of flamingos be f and elephants e.

Number of animals:

• f + e = 16

Number of legs:

• 2f + 4e = 52

Simplify:

• f + 2e = 26

Substitute f + e:

• (f + e) + e = 26
• 16 + e = 26
• e = 10

Find f:

• f = 16 - e
• f = 16 - 10
• f = 6

There are 6 flamingos and 10 elephants