Answer:
Step-by-step explanation:
Step-by-step explanation:
I would write the growth function as:
y
=
100
e
k
t
So that at
t
=
0
we get:
y
=
100
e
0.02
⋅
0
=
100
bacteria.
At
t
=
5
hours we will get:
y
=
100
e
5
⋅
0.02
=
110
bacteria.
To double the initial number we need to solve:
200
=
100
e
0.02
t
e
0.02
t
=
2
Apply natural logs to both sides:
ln
(
e
0.02
t
)
=
ln
(
2
)
0.02
t
=
ln
(
2
)
t
=
ln
(
2
)
0.02
=
34.65
≈
34.6
34
hours and 36 minutes approx.