Question

A meter of polyaramide fiber has a diameter of 710.μm , a mass of 0.059g , and takes 0.13s to produce on an industrial spinneret. How would you calculate the mass of fiber that can be spun in 55.min ?

Answer 1

t = 55 min ⇒ m = 1497.692 g

Step-by-step explanation:

polyaramide fiber:

∴ L = 1 m

∴ d = 710 μm

∴ m = 0.059 g

∴ t = 0.13 s

mass flow:

∴ mf = 0.059 g / 0.13 s = (0.454 g/s)×(60s/min) = 27.23 g/min

If t = 55 min:

⇒ m = mf×t = (27.23 g/min)×(55 min) = 1497.692 g

Answer 2

`m_(fiber)=1497.7g`

Step-by-step explanation:

Hello,

In this case, as both the diameter and the length of the fiber is the same for the second case, one applies a simple rule of three to compute the mass of fiber that can be spun in 55 min as shown below:

`m_(fiber)=(55min*0.059g)/(0.13s*(1min)/(60s) )\\m_(fiber)=1497.7g`

Best regards.