Question

A vessel contains 18.06*10^23 molecules of ammonia gas at 25°c. Calculate the number of hydrogen atoms present in the ammonia gas.

Answer 1

Step-by-step explanation:

Before you use log you have to multiply the answer of 8.66 mol by 6.02⋅1023 by 3 because the answer of 8.66 mol by 6.02⋅1023 gives you the number of ammonia molecules and in each molecules there are 3 hydrogen atoms present.

So it is:

8.66⋅6.02⋅1023=5.21332⋅1024

5.21332⋅1024⋅3=1.563996⋅1025

log(1.563996⋅1025)=25.19

Answer 2

Answer:There are 5.418×10^24 hydrogen atoms present in the ammonia.

Step-by-step explanation:

Ammonia (NH3) is a molecule that exists as a gas at Standard temperature (298 K). It contains atoms of Nitrogen and Hydrogen in atomic ratio of 1:3. We can represent it in equation as:

N2 + 3H2 <------> 2NH3

One molecule of NH3 contains one atom of Nitrogen (N) and three atoms of Hydrogen (H). That is 3 atoms of Hydrogen are present in every 1 molecule of NH3. We can as well say that 1 atom of Hydrogen is present in 1/3 molecule of NH3.

Number of NH3 molecules = 1/3 × number of hydrogen atoms

Number of NH3 molecules = 18.06 × 10^23 molecules at 25°C

18.06× 10^23 molecules = 1/3 × number of hydrogen atoms

Cross multiply,

Number of hydrogen atoms= 3× 18.06×10^23 molecules

Number of hydrogen atoms= 5.418×10^24 atoms

Therefore, there are 5.418×10^24 hydrogen atoms present in the ammonia.