Question

A sound is recorded at 19 decibels. What is the intensity of the sound?

Answer 1

79·433 ×
`10^(-12)` W/m²

Step-by-step explanation:

Given intensity of sound in decibels is 19

Formula for intensity of sound in decibels is

`I_(1)` = 10 × ㏒(I ÷
`I_(0)`)

where

`I_(1)` is the intensity of sound measured in decibels

I is the intensity of sound measured in W/m²

`I_(0)` is the intensity of the sound that is taken as standard and it's value is equal to
`10^(-12)` W/m²

By applying the formula

19 = 10 × ㏒(I ÷
`I_(0)`)

⇒ 1·9 = ㏒(I ÷
`I_(0)`)

⇒ antilog(1·9) = I ÷
`I_(0)`

⇒ 79·433 = I ÷
`10^(-12)`

⇒ I = 79·433 ×
`10^(-12)` W/m²

∴ Intensity of sound = 79·433 ×
`10^(-12)` W/m²