Question

What is the equation of the graph below?

A) y = − (x − 3)^2 + 1
B) y = − (x + 3)^2 + 1
C) y = (x − 3)^2 − 1
D) y = (x + 3)^2 − 1

Answer 1

Answer is D. No negative in front because the parabola opens upwards. x+3 moves it left 3. And - 1 moves it down one