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What is the equation of the graph below? A) y = − (x − 3)^2 + 1 B) y = − (x + 3)^2 + 1 C) y = (x − 3)^2 − 1 D) y = (x + 3)^2 − 1

What is the equation of the graph below? A) y = − (x − 3)^2 + 1 B) y = − (x + 3)^2 + 1 C) y = (x − 3)^2 − 1 D) y = (x + 3)^2 − 1
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What is the equation of the graph below?

A) y = − (x − 3)^2 + 1
B) y = − (x + 3)^2 + 1
C) y = (x − 3)^2 − 1
D) y = (x + 3)^2 − 1

What is the equation of the graph below? A) y = − (x − 3)^2 + 1 B) y = − (x + 3)^2 + 1 C-example-1
User Miroslav Nedyalkov
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1 Answer

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Answer is D. No negative in front because the parabola opens upwards. x+3 moves it left 3. And - 1 moves it down one
User DragonAssassin
by
8.5k points
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