Question

Write an equation of the line that passes through a pair of points: (-4,-3), (-3,1)

Answer 1

The equation of the line is 4 x - y + 13 = 0.

Explanation:

Here the given points are ( -4, -3) & ( -3, 1) -

Equation of a line whose points are given such that

(
`x_(1), y_(1)` ) & (
`x_(2), y_(2)` )-

y -
`y_(1)` =
`( y_(2) - y_(1) )/( x_(2) - x_(1) )` ( x -
`x_(1)` )

i.e. y - (-3) =
`( 1 - (-3))/( (-3) - (-4))` ( x- (-4))

y + 3 =
`(1 + 3)/( -3 + 4)` ( x + 4 )

y + 3 =
`(4)/(1)` ( x + 4 )

y + 3= 4 ( x + 4)

y + 3 = 4 x + 16

4 x - y + 16 - 3 = 0

4 x - y + 13 = 0

Hence the equation of the required line whose passes trough the points ( -4, -3) & ( - 3, 1) is 4 x - y + 13=0 .