The equation of the line that cuts through (0,5) and (1,2) is y = -3x + 5
Solution:
Given that we have to find equation of the line that cuts through (0,5) and (1,2)
The equation of line passing through points
and
is given as:
![y - y_1 = m(x - x_1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4exoxzl9wyc78rb7vje3c9oxdf7c81fpof.png)
Where "m" is the slope of line
Let us first find slope of line
The slope of line is given as:
![m=(y_(2)-y_(1))/(x_(2)-x_(1))](https://img.qammunity.org/2020/formulas/mathematics/high-school/3fxtemrxoojbluu7ia4t5ray7mr5l0mruj.png)
![\text{ Substituting } (x_1, y_1) = (0, 5) \text{ and } (x_2, y_2) = (1, 2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8uc8uzj3f7pb0glu2in7qtfjbnjcy0os3v.png)
![m=(2-5)/(1-0)=-3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/i2crz9bh5rju0bdyhybs2x4p7iaww2anm6.png)
Thus the required equation of line is:
![y - 5 = -3(x - 0)\\\\y - 5 = -3x\\\\y = -3x + 5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fqdbwxrsga8m2mjix7pocnhnrc5408h3dy.png)
Thus the equation of line is found