Question

Anyone please help me solve the area of parallelogram

Answer 1

Therefore the area of parallelogram is 32 cm².

Explanation:

Given:

[] ABCD is a Parallelogram .........Given

AB = 4 cm = Base

BC = 10 cm

CE = Height of Parallelogram

To Find:

area of parallelogram = ?

Solution:

In Right angle triangle BEC by Pythagoras theorem we have

`(\textrm{Hypotenuse})^(2) = (\textrm{Shorter leg})^(2)+(\textrm{Longer leg})^(2)`

Substituting the values we get

`10^(2)=6^(2) +CE^(2) \\\\CE^(2)=100-36=64\\ \\\therefore CE = 8\ cm\\`

Which is the Height of Parallelogram

Now, area of parallelogram given by

`\textrm{Area of Parallelogram} = Base* Height`

Substituting the values we get

`\textrm{Area of Parallelogram} = 4* 8=32`

`\textrm{Area of Parallelogram} = 32\ cm^(2)`

Therefore the area of parallelogram is 32 cm².