Question

In right triangle JKL, ZL is a right angle, mZJ = 62°, and JK = 17.

sin 62° 0.88
cos 62° 0.47
tan 62° 1.88
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What is the measurement of JL?
If necessary, round your answer to one decimal place, like this: 42.5

Answer 1

Please the attachment for question.

Answer:

Measurement of JL=8

Explanation:

Given:-

`\triangle JKL\ is\ right\ angle\ triangle`

`m\angle J=62\ degree`

JK=17

`sin\ 62\ degree= 0.88`

`cos\ 62\ degree= 0.47`

`tan\ 62\ degree= 1.88`

To find measurement of JL=?

Now,

`cos\theta=(adjacent\ side)/(hypotenuse)`

`cos\ 62\ degree=(JL)/(17)`

`0.47=(JL)/(17)`

`JL=0.47* 17`

`JL=7.99`

`JL=8`

Therefore measurement of JL=8