Answer:
B. 3,4 Volt
Explanation:
Here we need to use Ohm's Law, because we have electric current, voltage and resistances. This law state:
![V=IR](https://img.qammunity.org/2020/formulas/chemistry/middle-school/54vvj0rpb2pdb10injvqqtxro0369imuvo.png)
So, first we need to calculate the total resistance to then find the voltage. The resistances can be placed in two ways: in parallel, in series.
The pair 4 and 8 ohms are parallel, so we solve:
![R_(T)=(1)/(R_(1))+(1)/(R_(2))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bikd7ncw3pwf8xn3eghdtd6cl47wa0nehk.png)
![(1)/(R_(T))=(1)/(4)+(1)/(8)=(8+4)/(32)=(12)/(32)=(3)/(8)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hygw3nogwje79emliga71fj078zup33trv.png)
Which is,
![R_(T)=frac{8}{3}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8rrvs2t9xw12lvii2mq3o2yvhgl7nrq8m0.png)
Now, this total resistance of parallels ones is placed in series with the 3 ohm resistance, in this case we just sum, because they are in series:
![R=3+(8)/(3)=(9+8)/(3)=(17)/(3)=5.67 ohm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/id6huop41uisut6kr359f2grmgkfbt9pqj.png)
Now that we have the total resistance of the circuit, we use the Ohm's Law:
![V=IR\\V=(0.6A)(5.67ohm)=3.4 Volt](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nw8inm9tccfi68zy6ooai7upubym3p6ghd.png)
Therefore, the right answer is B.