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90% of adult females have height h (in feet) that satisfies the inequality h-5.350.21≤2.PEO8u1R7JRMqpfyKkyBAiu7m2VSa2P1jS2VeRvrV (SLO #2) Solve the inequality. Show your work. Interpret the meaning of your answer to part (a) in the context of this problem. Based on your answer to part (b), would it be unusual to encounter a female who was 5'9" tall? Explain.

2 Answers

4 votes

Answer:

?

Explanation:

User Ratnanil
by
5.3k points
3 votes

Answer:

4.93 =< h =< 5.77

a) 90% woman (most of them) are within the height of 4.93 and 5.77 ft

b) not unusual since it is within the range

Note: for this answer, I'll use the following symbols:

=< as less or equal

=> as more or equal

Explanation:

The inequality is

Abs[(h-5.35)/0.21)] = < 2

The absolute value sign will causes the value in the abs() bracket to be zero, whether the value is positive or negative

In other word, (h - 5.35)/0.21 could actually be a negative or positive

We consider both possibility

If it's positive: (h - 5.35)/0.21 =< 2

If it's negative: (h - 5.35)/0.21 => -2

Note that if we consider it as negative, the inequality sign change because at negative value, the order of magnitude is inverted to positive values.

Let's consider the positive first:

(h-5.35)/0.21 =< 2

h =< 2*0.21 +5.35

h =< 5.77

And then the negative

(h - 5.35)/0.21 => -2

h => -2*0.21 + 5.35

h => 4.93

From both calculation we can see that the range value of h is

4.93 =< h =< 5.77

a) this means that 90% of woman height is between 4.93 to 5.77 feet

b) 5'99'' = 5.75 ft

The height is within the range found from this calculation. So it's not that unusual.

User Simia
by
5.0k points