Question

A chemist fills a reaction vessel withmercurous chloridesolid,mercury (I)aqueous solution, andchlorideaqueous solution at a temperature of.Under these conditions, calculate the reaction free energyfor the following chemical reaction:Use the thermodynamic information in the ALEKS Data tab. Round your answer to the nearest kilojoule.

Answer 1

Free energy change of the reaction is +98.83 kJ/mol.

Step-by-step explanation:

The dissociation reaction of mercury(I) aqueous solution is as follows.

`Hg_(2)Cl_(2)(s)\rightarrow Hg_(2)^(2+)(aq)+2Cl^(-)(aq)`

The standard free energy of the reaction is as follows.

`\Delta G_(rxn)^(o)=m\Delta G^(o)(products)-n\Delta G^(o)_(reactants)`

`=[(1* \Delta G^(o)_{f(Hg_(2)^(2+))})+(2* \Delta G^(o)_(f(Cl^(-))))-(1* \Delta G^(o)_{f(Hg_(2)Cl_(2))})]`

`=[(1* 153.5+2* -131.25)-(1* -210.78)]kJ=+101.78kJ`

`Gas\,constant`

`Temperature=25^(o)c=25+273=298K`

`Free\,energy\,change\,of\,the\,reaction=\Delta G=\Delta G^(o)+RT\,lnQ`

`\Delta G=\Delta G^(o)+RT\,ln([Hg_(2)^(2+)][Cl^(-)]^(2))`

`=(101.78kJ)+8.314* 10^(-3)kJK^(-1)mol^(-1)*298K ln((0.926)(0.573)^(2))`

`=(101.78kJ)+(-2.95kJ)=+98.83kJ/mol`

Therefore, Free energy change of the reaction is +98.83 kJ/mol.