Question

Kim drove from Mathtown at (-2, 5) to Geometryville at (3, -1) to Algebra Springs at (-6, -5), and then back to Mathtown. Find the total distance Kim traveled to the nearest hundredth.

Answer 1

33.38 km

Explanation:

Kim drove from Math Town at (-2, 5) to Geometry Ville at (3, -1) to Algebra Springs at (-6, -5), and then back to Math town.

Now, the distance from (-2,5) point to (3,-1) point will be

`\sqrt{(- 2 - 3)^(2) + (5 - (-1))^(2)} = √(61)` km.

Again, the distance from point (3,-1) and (-6,-5) point will be

`\sqrt{(3 - (- 5))^(2) + (- 1 - (- 5))^(2)} = √(80)` km.

Therefore, the total distance Kim traveled will be =
`2(√(61) + √(80)) = 33.38` Km. (Answer)

The distance between two points
`(x_(1),y_(1))` and
`(x_(2),y_(2))` on the coordinate plane is given by

`\sqrt{(x_(1) - x_(2))^(2) + (y_(1) - y_(2))^(2)}`