Answer:

Explanation:
A. Knowing that the functions are:

You need to add them in order to find
. Then, you get:

To find:

Substitute
into
and evaluate.
Then, this is:

B. The functions f(x) and g(x) are:

You need to subtract them in order to find
:

To find:

Substitute
into
and evaluate.
Then, this is:
