Question

Given the reaction:

3 Cu +8 HNO3 → 3 Cu(NO3)2 + 2 NO + 4 H2O
The total number of grams of Cu needed to produce
1.0 mole of Cu(NO3)2 is
A) 64 B) 32 C) 128 192

Answer 1

To produce 1.0 mole of Cu(NO3)2, 63.55 grams of Cu are required according to the stoichiometry of the balanced chemical equation, which slightly exceeds option (A) 64 grams when taking into account the precise molar mass of Cu.

Step-by-step explanation:

To determine the total number of grams of Cu needed to produce 1.0 mole of Cu(NO3)2, we look at the stoichiometry of the balanced chemical equation:

3 Cu + 8 HNO3 → 3 Cu(NO3)2 + 2 NO + 4 H2O.

According to this balanced equation, 3 moles of Cu produce 3 moles of Cu(NO3)2. This means that 1 mole of Cu will produce 1 mole of Cu(NO3)2. The molar mass of Cu is approximately 63.55 grams per mole. So, to produce 1 mole of Cu(NO3)2, the mass of Cu required is:

63.55 grams of Cu.

Thus, the answer is slightly over option (A) 64 grams, as we need to consider the actual molar mass of Cu (63.55 g/mol). Therefore, 1 mole of Cu(NO3)2 corresponds to roughly 63.55 grams of Cu.

Answer 2

option A : 64 g

Step-by-step explanation:

Data Given:

no. of moles Cu(NO₃)₂ = 10 moles

mass of Cu = ?

Reaction Given:

3Cu +8HNO₃ ------→ 3Cu(NO₃)₂ + 2NO + 4H₂O

Solution:

First we have to calculate moles of Copper that react and moles of Cu(NO₃)₂ that produce in reaction :

For this look at reaction

3Cu +8HNO₃ ------→ 3Cu(NO₃)₂ + 2NO + 4H₂O

3 moles 3 moles

As 3 moles of Cu react to produce 3 moles of Cu(NO₃)₂

So,

1 mole of Cu (copper) will produce 1 mole of Cu(NO₃)₂

Now find the mass of 1 mole Cu (copper)

For this purpose formula used

mass in grams = no.of moles x molar mass

molar mass of Cu = 64 g/mol

Put values in above formula

mass in grams = 1 mol / 64 g/mol

mass in grams = 64 g

So 64 g of Cu is required to produce 1 mole of Cu(NO₃)₂

option A is correct.