Question

Find the distance between each pair of points.

6 units
5 units
2 units
4 units
3 units
E(-2, -1) and F(-2, -5)
arrowRight
C(-4, 1) and D(1, 1)
arrowRight
G(3, -5) and H(6, -5)
arrowRight
A (5, 4) and B( 5, -2)
arrowRight

Answer 1

G(3, -5) and H(6, -5) ------>3 units

arrowRight

E(-2, -1) and F(-2, -5)------->4 units

arrowRight

A (5, 4) and B( 5, -2)------->6 units

arrowRight

C(-4, 1) and D(1, 1)---------->5 units

arrowRight

Step-by-step explanation:

Answer 2

The distances are:

- E and F: 4 units.

- C and D: 5 units.

- G and H: 3 units.

- A and B: 6 units.

Why?

We can find the distance between each pair of points using the following formula:

`d(P_1,P_2)=\sqrt{(x_2-x_1)^(2)+(y_2-y_1)^(2)}`

So, calculating we have:

- E(-2, -1) and F(-2, -5):

`d(E,F)=\sqrt{(-2-(-2))^(2)+(-5-(-1))^(2)}\\\\d(E,F)=\sqrt{0+(-5+1)^(2)}=\sqrt{0+(-4)^(2)}=√(16)=4units`

- C(-4, 1) and D(1, 1):

`d(C,D)=\sqrt{(1-(-4))^(2)+(1-(1))^(2)}\\\\d(C,D)=\sqrt{(5)^(2)+0^(2)}=√(25+0)=√(25)=5units`

- G(3, -5) and H(6, -5):

`d(G,H)=\sqrt{(6-(3))^(2)+(-5-(-5))^(2)}\\\\d(G,H)=\sqrt{(3)^(2)+0^(2)}=√(9+0)=√(9)=3units`

- A(5, 4) and B( 5, -2):

`d(A,B)=\sqrt{(5-(5))^(2)+(-2-(4))^(2)}\\\\d(A,B)=\sqrt{0+(-6)^(2)}=√(0+36)=√(36)=6units`

Have a nice day!