Question

I don’t understand this help please

Answer 1

9

Explanation:

The first simplification we can make is to replace 6^0 with 1.

The first rules of exponents we can apply are ...

(a·b)^c = a^c·b^c . . . . . . similar to the distributive property

(a^b)^c = a^(b·c)

This reduces your expression to ...

`(2^8\cdot 3^(-5))^(-2)\cdot\left((3^(-2))/(2^3)\right)^4\cdot 2^(28)=2^(8(-2))\cdot 3^(-5(-2))\cdot(3^(-2(4)))/(2^(3(4)))\cdot 2^(28)\\\\=2^(-16)\cdot 3^(10)\cdot(3^(-8))/(2^(12))\cdot 2^(28)`

Now we can apply another two rules of exponents:

(a^b)(a^c) = a^(b+c)

1/a^b = a^-b

Using these, we have ...

`=2^(-16-12+28)\cdot 3^(10-8)\\\\=2^0\cdot 3^2\\\\=1\cdot 9=9`

The value of the expression is 9.